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8x^2-159x+758=0
a = 8; b = -159; c = +758;
Δ = b2-4ac
Δ = -1592-4·8·758
Δ = 1025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1025}=\sqrt{25*41}=\sqrt{25}*\sqrt{41}=5\sqrt{41}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-159)-5\sqrt{41}}{2*8}=\frac{159-5\sqrt{41}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-159)+5\sqrt{41}}{2*8}=\frac{159+5\sqrt{41}}{16} $
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